7(x^2+4x+4)-12=16

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Solution for 7(x^2+4x+4)-12=16 equation:


Simplifying
7(x2 + 4x + 4) + -12 = 16

Reorder the terms:
7(4 + 4x + x2) + -12 = 16
(4 * 7 + 4x * 7 + x2 * 7) + -12 = 16
(28 + 28x + 7x2) + -12 = 16

Reorder the terms:
28 + -12 + 28x + 7x2 = 16

Combine like terms: 28 + -12 = 16
16 + 28x + 7x2 = 16

Add '-16' to each side of the equation.
16 + 28x + -16 + 7x2 = 16 + -16

Reorder the terms:
16 + -16 + 28x + 7x2 = 16 + -16

Combine like terms: 16 + -16 = 0
0 + 28x + 7x2 = 16 + -16
28x + 7x2 = 16 + -16

Combine like terms: 16 + -16 = 0
28x + 7x2 = 0

Solving
28x + 7x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '7x'.
7x(4 + x) = 0

Ignore the factor 7.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {0, -4}

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